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particles of charge +75,+48 and -85 uC are placed in a line. The center one is 0.35m from each of the others. Calculate the net force on each charge due to the other two.
I actually have the solution, but i dont know where they get r=12, r=23 and r=13? and that "r" part is what i dont understand
PLEASE HELP !

2007-03-21 14:49:51 · 1 answers · asked by Linda 1 in Science & Mathematics Physics

1 answers

I DON'T HAVE THE BOOK SO
(since the principal is the same)
Let
q1=+75,
q2=+48
q3= -85 uC
let q2 be in the middle
F=kq1q2/R^2

F2=-F12+F23
F2=k(-q1q2/R12^2 + q2q3/R23^2 ) since R12=R23
R12- distance between charge 1 and charge 2
R23 - distance between charge 2 and charge 3
F2=k/R^2(-q1q2+q2q3)
The rest is arithmetic
Does that help?

2007-03-23 08:13:44 · answer #1 · answered by Edward 7 · 0 0

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