tom went to an ice cream store that has 15 different flavors.
1. she wanted a sugar cone with three different scoops of ice cream. she is being very picky and the order of the scoops matters to him. how many different possibilities does he have to choose from?
2. he changed his mind and decided on a hot fudge sundae with three scoops of ice cream in a bowl. how many defferent [ossibilities does he have to choose his ice flavors if he does not repeat any flavor?
(does the order matter when the ice cream is in a bowl)
please help.
waiting ur help.
thanks.
2007-03-21 12:26:15 · 6 answers · asked by inayare 1 in Education & Reference ➔ Trivia
Ok, this is just like the question about combinations you asked before...
1) 15 types, 3 scoops.
15 P 3 =
15! / (15-3)! =
(15x14x13x12x11x10x9x8x7x6x5x4x3x2x1) / (12x11x10x9x8x7x6x5x4x3x2x1) =
2730 different possible combinations of 3 scoop cones.
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2) This part of the question required a little more work, but luckily you have the first part done in the first part of this question...
Since we already know that 15P3 = 2370, we only have to find out the answer, getting rid of the duplicates of flavors (15C3).
15C3 =
15 P 3 / 3! =
15! / 3! x 12! =
(15x14x13x12x11x10x9x8x7x6x5x4x3x2x1) / (3! x (15 -3)! =
(15x14x13x12x11x10x9x8x7x6x5x4x3x2x1) / ( (3x2x1) x (12x11x10x9x8x7x6x5x4x3x2x1) =
(15x14x13) / (3x2x1) =
455 possible combinations without repeating a flavor.
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2B) The order does not matter because no flavor is repeated.
2007-03-21 13:08:38 · answer #1 · answered by Pauly 3 · 1⤊ 0⤋
1. 9 different possibilities
2. 9 different possibilities
2007-03-21 14:01:01 · answer #2 · answered by Shafer Emma Katherine 1 · 0⤊ 2⤋
You can figure this out for yourself or I can do it for you and you can use my answers.
1. 3*15=45-3= 42 choices
2. 3*3=9*12=108 choices
Hope you take my help and get them wrong. Do your own school work! :-P
2007-03-21 12:38:22 · answer #3 · answered by Anonymous · 0⤊ 4⤋
no it doesn't matter and on the 1st one try multiplying 3x3
and I would try multiplying 3x15 on the 2nd one, I have questions like these all the time
2007-03-21 12:33:10 · answer #4 · answered by Anonymous · 0⤊ 3⤋
Try looking through this website on combinations and permutations: http://www.mathsisfun.com/combinatorics/combinations-permutations.html.
HTH!
2007-03-21 12:32:22 · answer #5 · answered by yanksfan 2 · 0⤊ 4⤋
?? do ya own work its really EASY!!!
2007-03-21 12:29:44 · answer #6 · answered by LaDanna 2 · 0⤊ 4⤋