HEEEEEEELP THE MATH! SOMEBoDY HELP ME WITH THE MATH! PLEASE....?

Question

I need quick help with math!!!!!!!?
lorenzo's pizzeria offer 10 different pizza topping, including pepperoni, garlic, pinapple, and black olive.
1. how many different three-topping pizza are possible?
2. how many different four-topping pizza are possible?
3.how many of the possible four-topping pizza do not include pepperoni or black olives?

please help!!!!!!
I am waiting you help.
thank you.

Answer 1

1. 720 combinations
2. 5040 combinations
3. 1680 combinations

To solve: if there was one topping, it would be ten, right? Now how about two toppings? You could use numbers and write all the possibilities, but the answer is 90. Why? 10 x 9. The first topping, there are ten possibilities. But for the second, there are only nine toppings left to choose from.

Now apply this to three toppings: 10 topping for the first choice, 9 for the second, and 8 for the third. 10 x 9 x 8 = 720 (yes, a lot!)

Now for four toppings: 10 topping for the first choice, 9 for the second, 8 for the third, and 7 for the fourth. 10 x 9 x 8 x 7 = 5040

As for your third problem, same system of solving, but now you only have eight toppings to choose from (10 toppings minus pepperoni and black olives). So, 8 choices for first, 7 for the second, etc.... 8 x 7 x 6 x 5 = 1680

Hope this helps....

Answer 2

so some distance, you have 25 & one 0 five stages accounted for. jointly, that makes a hundred thirty stages, so the the rest attitude might desire to be 50 stages. then you certainly're arranged to apply the regulation of Sines. i'll apply "a" for the edge opp. attitude A, "b" for the edge opp. attitude B, & "c" for the edge opp. attitude C. and of path, we already understand that edge c = 50. Then we've 50 / sin 50 = a / sin one 0 five and 50 / sin 50 = b / sin 25 All of those angles might desire to declare stages, of path. Now remedy those 2 eqns for a & b and there you're. i propose you to isolate the unknown letter formerly crunching it out on the calculator, so which you will not do any rounding until the top of the subject, giving a extra precise answer, and of path be certain the calculator is desperate on stages and not radians. notice that with the regulation of Sines, the reciprocals could be used. the two will artwork as long as you're consistent. Why won't SohCahToa artwork in this problem? this is not a precise triangle. Why will regulation of Sines artwork? With regulation of Sines, it does not might desire to be a precise triangle. you in basic terms write out the equations, and all you want is 3 out of four of the unknowns in each and each eqn. then you certainly can say, "Aha! i can use the regulation of Sines," and bypass precise forward & do it. have exciting!

Answer 3

u need to draw a tree diagram.. look that up