Two-thirds of a club voted for pizza for snack 1/2 of other were popcorn rest split for candy fruit 5 #of kids

Question

Two-thirds of a club voted for pizza as their favorite snack. One half of the other votes were for popcorn. The remaining votes were evenly split between candy and fruit. If fruit received 5 votes how many kids in club?

Answer 1

Is this supposed to be a trick question?

Well all I know is that two thirds is pizza. Half of what is left is popcorn So that means One- sixth is popcorn. Now you have one sixth left then candy and fruit had to both receive 5 votes.(I think) so with in the candy and fruit there is 10 votes. the one- sixth is 20 votes and then two- thirds is 80 votes. add the total together and the answer is 110 votes. (This answer may not be right) But this is what I got!
110 Kids in club!

Answer 2

that should not be hard :
T = total club members

pizza 2/3T
other 1/3 T
popcorn = 1/2 * 1/3 T = 1/6 T
fruit = 1/2 * 1/3 T = 1/6 T = 5
so T= 5 * 6 = 30
30 kids

Answer 3

let x = number of kids

2/3x want pizza. that leaves 1/3x remaining.
of that 1/3x remaining, 1/2 want popcorn, so 1/3x * 1/2 =1/6x.
fruit = 5
candy = 5

2/3x + 1/6x + 5 + 5 =1x
10 = 1x - 2/3x - 1/6x
10 = 6/6x - 4/6x - 1/6x
10 = 1/6x
x = 60

so there are 60 kids in total in the club
hope this helps