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In his motorboat, Bull Ruhberg travels upstream at top speed to his favorite fishing spot, a distance of 36 mi, in 2 hr. Returning, he finds that the trip downstream, still at top speed, takes only 1.5 hr. Find the speed of Bill's boat and the speed of the current.

2007-03-21 07:58:45 · 4 answers · asked by World Expert 1 in Education & Reference Homework Help

4 answers

That's a strange name. Anyway, the name doesn't matter.
If the current downstream is x mph and the boat's speed in still water is y mph, then:
From the trip upstream, 36 = 2(y-x)
36 = 2y - 2x
y - x = 18 ..................(1)
From the trip downstream, 36 = 1.5(y+x)
y + x = 36/1.5 = 72/3
y + x = 24 .................(2)
Add (1) and (2):
2y = 42
y = 21.
Subtract (1) from (2):
2x = 6
x = 3
Bill's boat has a top speed of 21mph in still water, and the speed of the current is 3mph.

2007-03-21 08:35:57 · answer #1 · answered by Anonymous · 0 0

This is a pretty straightforward distance equals rate x time problem. First, calculate the rate (r1) for Bull's upstream trip and then for his return (r2). The speed of the current will be 1/2 the difference between the two rates: r2-r1 / 2. To determine the boat's speed, either add the current speed to Bull's upstream rate (r1) or subtract the current speed from Bull's downstream rate (r2).

2007-03-21 08:30:36 · answer #2 · answered by Anonymous · 0 0

$30 VIP tickets= X $18 = a million/5X $10= 11/5X 10(11/5X)+ 18(a million/5X) + 30(X) = 9500 22X+ 18/5X + 30X= 9500 278/5X=9500 278X= 40 seven,500 X=171 $30 = 171 Tickets $18 = 34 Tickets $10 = 376 Tickets

2016-11-27 20:06:25 · answer #3 · answered by ? 4 · 0 0

Your system will look like this:

2x = 36 miles
1.5x = 36 miles

Add the two equations together to yield:

3.5x = 72 miles

Divide 72 by 3.5:

x = about 21 mph.

I hope that's right.

2007-03-21 08:15:56 · answer #4 · answered by mericafyeah 2 · 0 0

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