2007-03-21 07:38:03 · 30 answers · asked by Anonymous in Entertainment & Music ➔ Music
blondie admits shes #$%^&* up so her
2007-03-21 07:40:18 · answer #1 · answered by Juleette 6 · 3⤊ 1⤋
You're kidding right?! You can't even begin to compare an amazing band like Blondie to a teen singer like Britney. Debbie Harry has SO much more talent than Britney Spears, Debbie has a beautiful voice and is a phenomenal singer, all Britney has is an okay set of pipes and lots of computer support. Blondie wins...no contest!
2007-03-21 18:41:47 · answer #2 · answered by sunday girl 6 · 0⤊ 0⤋
Blondie was pretty good back in the late 70's.
Are you comparing her today with today's Britney?
Not really a fair comparison.
Now, based on quality of songs, both were kinda predictable pop divas.
I'd still be more likely to buy a Blondie CD than a Brit CD, just because there is more substance in the musical style.
2007-03-21 14:44:15 · answer #3 · answered by docscholl 6 · 0⤊ 0⤋
Blondie
2007-03-21 14:40:30 · answer #4 · answered by primamaria04 5 · 3⤊ 0⤋
What a total night & day comparison!
BLONDIE! Britney is not only out of Deborah Harry's league, but it's near blasphemy to mention her in the same sentence as Blondie!
2007-03-21 14:48:40 · answer #5 · answered by Fonzie T 7 · 1⤊ 0⤋
Blondie, Britney sounds like trash!
2007-03-21 14:40:24 · answer #6 · answered by Anonymous · 4⤊ 0⤋
Blondie.
2007-03-21 14:40:53 · answer #7 · answered by Anonymous · 3⤊ 0⤋
blondie britney sounds like a teenage girl
2007-03-21 14:40:49 · answer #8 · answered by jojo 5 · 1⤊ 0⤋
Blondie...whose real name is Debbie Harry...sounds so much better...how can you even compare her to Britney Spears?
2007-03-21 14:51:44 · answer #9 · answered by Lori O 2 · 0⤊ 0⤋
Blondie (Debbie Harry) Heart of Glass...love it. Britney who?
2007-03-21 14:44:39 · answer #10 · answered by sarge 6 · 2⤊ 0⤋
Hands down...Blondie! Britney is just an over-marketed singer with very little talent! They aren't even in the same category!!
2007-03-21 14:42:14 · answer #11 · answered by lisagoesshopping 3 · 3⤊ 0⤋