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Ethylamine (C2H5NH2) has a pKb= 3.53. Determine the pKa of its conjugate acid (C2H5NH3+) if pKw=13.6

2007-03-21 06:41:19 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

We know that:

pKa + pKb = pKw

then:

pKa = pKw - pKb
pKa = 13.6 - 3.53 =
pKa = 10.07

That's it!

Good luck!

2007-03-21 06:45:40 · answer #1 · answered by CHESSLARUS 7 · 0 0

I'm going to pKa you!

2007-03-21 06:43:48 · answer #2 · answered by Anonymous · 0 1

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