A 17.9 ohm and a 20.6 ohm resistor are connected
parallel. A difference in potential of 47.9 V is
applied to the combination.
a)What is the equivalent resistance of the
parallel circuit? Answer in units of ohms.
b)What is the current in the circuit? Answer in
units of A
c)How much current passes through the 17.9 ohm
resistor? Answer in units of A.
2007-03-21 06:38:39 · 5 answers · asked by kpm0729 1 in Science & Mathematics ➔ Physics
Ohms Law my friend http://www.the12volt.com/ohm/ohmslaw.asp#pie
2007-03-21 06:42:41 · answer #1 · answered by westside_hooligan 3 · 0⤊ 0⤋
a) equivalent resistance is 9.58 ohms
b) current in circuit is 5A
c) 2.67 A current passes through 17.9 ohm resistor
2007-03-21 13:55:49 · answer #2 · answered by Abhinesh 4 · 0⤊ 0⤋
I = (E / R) sooo figure out your resistance and you can complete this equation in terms of current ( I ).
The Resistance requires the parallel formula ...which is ...
1/ R = 1/17.9 + 1/ 20.6
1/R = .0558 + .0485
1/R = .1043
R = 1/ .1043
R = 9.58 Ohms
now ....
I = E/ R
I = 47.9 / 9.58
I = 5 Amps
Resistance = 9.58
Current = 5 Amps
2007-03-21 13:50:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋
a) equivalent resistance R
R = R1R2/(R1+R2) = 9.58 ohm
b) current I
I = V/R = 47.9V/9.58ohm = 5.00 A
c) current through the 17.9 ohm resistor is
I = V/R = 47.9V/17.9ohm = 2.66 A
2007-03-21 14:11:06 · answer #4 · answered by catarthur 6 · 0⤊ 1⤋
Given:-
R1=17.9 ohm
R2=20.6 ohm
V=47.9 V
a) equivalent resistance R = R1 x R2 /(R1+R2)
=17.9 *20.6/(17.9 +20.6)
= 9.58 ohms
b) I =V/R
= 47.9/9.58
=5 A
c) I (r1)= I R2/(R1+R2)
=5*20.6/(17.9 +20.6)
=2.675A
2007-03-21 13:58:01 · answer #5 · answered by money money 3 · 0⤊ 0⤋