An object (mass 10.0kg) slides upward on a slippery vertical wall. A force of 60N acts at an angle of 60 degrees. I need to find the normal force and the objects acceleration. I understand this is hard when you cannot see the diagram that is provided, but if you can just give me an explaination on how I am suppose to answer this question I will apprciate it. Thanks so much!
2007-03-21 06:12:53 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
OK since the figure wasn't there i supposed that the force is acting on body at 60 degrees with the vertical so, we get two equations,
Fcos60-mg=ma
60*0.5-10*9.8=10*a
solving we get a=5.8m/s2 in downward direction.
also we get
Fsin60=N(normal reaction from wall)
60*1.732/2=N
i hope that solves your problem.
2007-03-21 06:37:58 · answer #1 · answered by Abhinesh 4 · 0⤊ 0⤋
You have not mentioned whether the 60 degrees is with respect to the horizontal or with the vertical... but anyways you have to find the horizontal component of the force acting on the object which is 60*cos 60. By newton's third law, the wall must exert an equal and opposite force on the object. So the normal force must be mass times force ( that is 10 * 60 * cos 60).
So the answer is 300 N.
2007-03-21 13:25:33 · answer #2 · answered by Shyam Sundar 2 · 0⤊ 0⤋