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Is the air resistance greater than the friction or is the friction greaterthan the air resisitance or are they balanced. plz help!!!

2007-03-21 06:00:25 · 5 answers · asked by nothing 1 in Science & Mathematics Chemistry

When its just taking off!!!!

2007-03-21 06:03:16 · update #1

can u plz just give me an anwser of one of the above plz ;]

2007-03-21 06:11:16 · update #2

5 answers

It depends on the speed.

Rolling friction is fairly *constant* in most cases, while Air friction is proportional to the square of the speed(up to transonic speeds)

F(roll) = C * N,

F(air) = k * v²,

where C, k are "coefficients of friction", N is the weight of the plane, and v is it's velocity. C and k are usually calculated by taking careful force measurements at different loads and speeds.

In order to find the speed at which the two forces are balanced, simply equate the two expressions..

k*v² = C*N, so solving this

v = sqrt(C * N / k)

Hope that makes sense,
~Donkey Hotei

P.s, Please ignore what "Curly" cut and pasted, it is totally irrelavent.

2007-03-21 06:28:52 · answer #1 · answered by WOMBAT, Manliness Expert 7 · 0 0

It's difficult to know what you mean by air resistance and friction. But when an object is moving through a medium such as air, it experiences drag or 'air resistance', which is the frictional force from the air that resists the forward motion of the object. So your question is rather confusing and I confess I am spending some time trying to unravel it. If by friction, you mean viscous forces, then they would be negligible in the case of air. In which case, the drag, ie. air resistance would be greater. Exactly how drag changes with speed depends on the shape of the plane and the properties of the surfaces, but roughly in proportional to the square of the speed.

2007-03-21 13:31:15 · answer #2 · answered by Anonymous · 0 0

The popular explanation of lift

Students of physics and aerodynamics are taught that airplanes fly as a result of Bernoulli’s principle, which says that if air speeds up the pressure is lowered. Thus a wing generates lift because the air goes faster over the top creating a region of low pressure, and thus lift. This explanation usually satisfies the curious and few challenge the conclusions. Some may wonder why the air goes faster over the top of the wing and this is where the popular explanation of lift falls apart.

In order to explain why the air goes faster over the top of the wing, many have resorted to the geometric argument that the distance the air must travel is directly related to its speed. The usual claim is that when the air separates at the leading edge, the part that goes over the top must converge at the trailing edge with the part that goes under the bottom. This is the so-called "principle of equal transit times".

As discussed by Gale Craig (Stop Abusing Bernoulli! How Airplanes Really Fly., Regenerative Press, Anderson, Indiana, 1997), let us assume that this argument were true. The average speeds of the air over and under the wing are easily determined because we can measure the distances and thus the speeds can be calculated. From Bernoulli’s principle, we can then determine the pressure forces and thus lift. If we do a simple calculation we would find that in order to generate the required lift for a typical small airplane, the distance over the top of the wing must be about 50% longer than under the bottom.

For more information see the attached website...

2007-03-21 13:05:33 · answer #3 · answered by Curly 4 · 1 1

I would say that air resistance and friction are proportional to the speed.
The faster you go, the greater they are.

2007-03-21 13:25:57 · answer #4 · answered by Norrie 7 · 0 0

it souds like you do need help.figre it out.go to
www.ask.com
then type it in.

2007-03-21 13:09:11 · answer #5 · answered by Anonymous · 0 1

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