a gas has a volume of 300 ml when under a pressure of 740mmHg. The temp remains constant.?

Question

calculate it's volume when under pressure of 750mm Hg

Answer 1

You can use Boyle's law:

P1V1 = P2V2

In this case:

V2 = P1V1 / P2
V2 = (740)(300) / 750 = 296 mL

That's it!

Good luck!

Answer 2

Boyle's Law: "The absolute pressure of a gas is inversely proportional to its volume at constant temperature".

P1V1 = P2V2

300 x 740 = 750 x V2

V2 = 300 x 740 ÷ 750

V2 = 296 ml

Answer 3

We can use P1V1/T1 = P2V2/T2

but T1 = T2, so these cancel out to give

P1V1 = P2V2

Therefore

V2 = (P1/P2) * V1

where P1= 740mm Hg and P2= 750 mm Hg, V1 = 300ml

V2 = (740/750)*300 = 296 ml.

Answer 4

Boyle's law
pV=k
p1V1 = k
p2V2 = k
so p1V1=p2V2
( 740 mm Hg) 300 mL = 750 mm HgV2
V2 = 304 mL

Answer 5

pV =nRT here nRT is constant so

p1V1 = p2V2

and V2 = p1V1/p2 p1 = 740 V1 =300 p2 =750

V2 = 300*740/750 =296 ml

Answer 6

you could relatively try this on your head. 60 (ml) divided by using 3 (to 40 5 PSI from 15 PSI is thrice the stress which = a million/3 the quantity) = 20ml for this reason, while stress is going up, quantity is going down. If this have been a reliable or liquid, the respond could have been distinctive.

Answer 7

If temp remains constant, then pressure is directly proportional to volume.

PV = n k T

If P increases then V must decrease.

750 / 740 = 1.013513514

300 / 1.013513514 = 295.9999999 ml

Answer 8

Use PV=nRT, since T is constant, then we will have

(PV)1 = (PV)2
740 x 300 = 750 x V2
V2 = 296 ml

Vol is 296 ml