I am desperat to find an old friend on the net,only everytime i log on to a people finder they want my to subscribe before i get any information,i just cant afford it.please help me,i have alot of history with this guy and if i dont find him soon it may be too late
2007-03-21 03:07:10 · 7 answers · asked by mancmilli 1 in Family & Relationships ➔ Friends
Myspace.com everybody has one. Most likely your friend will to. This where I find alot of my old friends till this day.
2007-03-21 03:11:01 · answer #1 · answered by bertinis_babe 1 · 0⤊ 0⤋
It really depends on how much background you know about this guy. Where did he go to highschool? Someone there might know, and if they don't, they'll know who the class president was/is, and they sometimes have information on where grads are at because of reunions. If you know his parents names, adults seldom move, and you can call them and ask where he is. Do you know of any places where he used to work? Searching for names in search engines could pay off, but its a long shot. Good Luck, I hope you find what you're looking for whether you find this guy or not. Peace.
2007-03-21 10:15:13 · answer #2 · answered by geehaw 4 · 0⤊ 0⤋
If you're in the UK, try 192.com. They have a free service and a subscription based one which will give you more info if you're interested.
2007-03-21 13:54:46 · answer #3 · answered by Fragile Rock 5 · 0⤊ 0⤋
You could try bigulo.com and if they have a Bebo page and (I THINK) a Myspace page, it'll come up.
Even if you don't find this particular friend, you'll find a lot of people from your past!
2007-03-21 11:37:52 · answer #4 · answered by lindaloo 2 · 0⤊ 0⤋
if your that bothered about reuniting with this guy, cough up the cash & stop being so stingy!
2007-03-21 13:41:33 · answer #5 · answered by helen b 3 · 0⤊ 0⤋
if you are in England and have details about this person....try this
http://www.b4usearch.com/
good luck
2007-03-21 10:58:38 · answer #6 · answered by Dazzlebox 7 · 0⤊ 0⤋
try friends reunited.com,good luck
2007-03-21 10:14:38 · answer #7 · answered by LYNDA M 5 · 0⤊ 0⤋