a. 10,000
b. 24
c. 3024
d. 5040
2007-03-21 02:24:45 · 12 answers · asked by lana l 1 in Science & Mathematics ➔ Mathematics
D
The first digit can be any of 10
The second digit can be any of the remaining 9
The third digit can be any of the remaining 8
The fourth digit can be any of the remaining 7
10*9*8*7 = 5040
This is, of course, assuming this is something like a password or access code and that leading zeros are valid.
2007-03-21 02:28:34 · answer #1 · answered by MamaMia © 7 · 0⤊ 0⤋
It's C (10,4)*P(4) = 10*9*8*7=5040
2007-03-21 02:32:15 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋
10*9*8*7 = 5040
2007-03-21 02:28:32 · answer #3 · answered by blighmaster 3 · 1⤊ 0⤋
d -5040 10*9*8*7=5040
2007-03-21 02:28:23 · answer #4 · answered by big cec 1 · 0⤊ 0⤋
10x9x8x7
the 1th place can be taken by 10digits (0....9)
the 10th place can be taken by 9 digits (0...9 except the number used in 1000th place
the 100th place can be taken by remaining 8 digits
the 1000st place by remaining 7 places
therefore the answer is 5040
2007-03-21 02:36:19 · answer #5 · answered by Kristy 2 · 1⤊ 0⤋
It is a permutation combination, where number of digits=10 (0,1,2,3....9) and number of digits used=4.
So the number of numerical codes =10!/(10-4)!
= 5040
So, the answer is D.
2007-03-21 02:36:15 · answer #6 · answered by Bubblez 3 · 0⤊ 0⤋
Answer is 10,000.
There are ten possible numbers (0-9) for each of the four positions in the code so it's simply 10 * 10 * 10 * 10 or 10^4 (10 to the 4th power).
2007-03-21 02:29:30 · answer #7 · answered by Gary C 1 · 0⤊ 3⤋
d: 10*9*8*7
2007-03-21 02:28:44 · answer #8 · answered by metalluka 3 · 1⤊ 0⤋
Thanks for this question. We are the manufacturers of four digit controlled burglar alarm. Now we can tell our customer that they can have 5040 combinations to operate our systems.
2007-03-21 03:06:00 · answer #9 · answered by A.Ganapathy India 7 · 1⤊ 0⤋
The first digit cannot be 0
so we get
9*9*8*7
=4536
none of the given coices fit
2007-03-21 02:36:35 · answer #10 · answered by Anonymous · 0⤊ 2⤋