The full formula would have to include the RMS voltage. But if you want a _very simple_ Ball park figure_ idea of the current capacity it is 1000/220 current input and 1000/110 current output.
or 4.5 amps on the input side and 10 amps on the output side
so, a 13 amp fuse on the input should be OK
2007-03-21 01:06:42
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answer #1
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answered by Vinni and beer 7
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For most purposes 1 KVa =1KW. Amps = Watts divided by Volts so you have 1000 watts divided by 220 volts which gives about 4 amps input and about double that on the output side. This means you can draw 8 amps on the output side. Limit it to that as the efficiency needs to be taken into account. I would fuse the input side at 3 amps if it is in continuous use but would risk 5 amps for intermittent use.
2007-03-21 02:58:39
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answer #2
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answered by Professor 7
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1KVA = 1000
voltage is 220. KVA = Voltsxamps
therefore 1000=220xI(amps)
I = 1000 divided by 220=4.5amps
2007-03-21 01:15:18
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answer #3
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answered by ANF 7
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If its a tool/site transformer it will have a 25% duty cycle you can use it for 5 minutes and "rest" the transformer for 15 minutes at 1000watt otherwise it will overheat(220v @ 4.5amp /110 v @ 9amp). For continuous use the rating is 60% of the rating on the transformer i.e. 600watt (220v @ 2.7amp/110 v @ 5.5amp)
2007-03-22 00:30:54
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answer #4
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answered by bryte 3
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it will draw 9.09 amps at 110 VAC or 4.45 amps at 220 VAC devide the input voltage by the KVA(1000 VA) and there is your answer. Paul
2007-03-21 03:24:06
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answer #5
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answered by Paul D 1
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1000 VA
1000 Volt (ampere)
V=IR
I=V/R
P=IV
I = 1000/220 = 4.54 A at the input
I = 1000/110 = 9.09 A at the load side
2007-03-21 01:10:36
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answer #6
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answered by Erizu 2
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The first two answers are correct, but if you intend to use the full output check the rating. It may be a 'Tool' transformer which will not be continuously rated and will overheat.
2007-03-21 01:19:04
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answer #7
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answered by jayktee96 7
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1kva Transformer
2016-11-09 21:10:04
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answer #8
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answered by ? 4
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