how do I find a set of coordinates on a graph from the gradient in y=14.5x+1.45?

Question

How do I find at least two coordinates on a graph that the line y=14.5x+1.45 passes through? Is there a formula that is used to find these coordinates? Or if the gradient equals 14.5, do I move 1 unit across, then 14.5 units up (so the coordinates would be (0,1.45) (1,15.45) ?

Answer 1

Just plug 3 different values of x into the equation, say x = 0, x = 5 and x = 10.
Work out the corresponding values of y.

Then just plot your points and draw a striaght line through them, that line will be a graph of-: y = 14.5 x + 1.45

Answer 2

it is a sraight graph so you only need two coodinates to complete the graph .

First of all substitute ( y = 0 ) into the eqn.
so
0 =1.45x + 1.45
1.45x = -1.45
x = -1
so the first coodinate is (-1 , 0 )

now substitute ( x = 0 ) into eqn.

y = 1.45 (0) + 1.45
y = 1.45

so the second coodinate will be ( 0 , 1.45 )

Answer 3

chose any value of x, for example chose x=1. if you substitute this into the equation
y=14.5(1) +1.45
= 15.95 this is the coresponding y value. therefore the coordinates are (1, 15.95)

Answer 4

Give x any value.
Examples
If x = 0,y = 1.45------ Point(0,1.45)
If x = 2,y = 29 + 1.45 = 30.45---Point(2,30.45)
If x = 10,y = 145 + 1.45 = 146.45--Point(10,146.45)