Electrons need two things to move. 1) A source and 2) A Destination. You see, electrons not only need to come from somehwere, but they need somewhere to go. This is where a circuit comes in...
Imagine a large circular race-track with a row of runners (one after the other). They start running around the track in circles. Suddenly, there's an earthquake and part of the track turns into a giant hole in the ground full of lava. Now, of course the runners are all going to stop at this point, as they can't go through lava.
Similarily, electrons can't travel through non-conductive material. Metal and water are very good conductors, which is why people can be electrocuted (our bodies contain a lot of water). When the electrons are blocked by something they cannot travel through, they stop.
I hope that answers your question!
2007-03-20 22:40:24
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answer #1
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answered by Keegarosan 2
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This is because when the wire is cut an air gap is formed between the 2 parts of the wire. Air being a BAD conductor of heat & electricity doesn't allow electrons to flow between the 2 ends where the wire has been cut .
But this is the case only if the potential applied is of less magnitude>
If a potential of VERY high volts is applied then the air between the 2 cut ends becomes ionized i.e. the atoms present in that part of the change into ions and the flow of electrons is possible.
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2007-03-20 22:50:57
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answer #2
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answered by Rishi_is_great 1
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Then why don't electrons jump out of a simply kept wire? These e that make up the current are parts of the wire itself. They collide with each other to transfer the energy. The drift velocity possesed by the e are so small that they are just sufficient 2 make the e collide with another.
Moreover I do hope u know the size of an e. How can u see them 'jump' from the wire, if they ever jumped(which doesn't happen)?
2007-03-20 22:43:43
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answer #3
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answered by Frendz 1
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The air has a high resistance, meaning that the charge carries are less likely to get through. If the electromotive force (terminal voltage) is large enough it will jump, due to the electrons being able to ionise the air, due to the larger amount of energy they have.
One could use this with momentum to explain it:
K.e = 1/2 m v(squared)
emf is proportional to K.e. of electrons
Or use these:
nAVE=I
n=volume density of charge carriers
A=cross-sectional area of wire
V=mean drift of electrons through the wire
E=the charge on the electron
I= Current
Then applying V=IR (Voltage = current x time) you eventually get the fact that velocity and mass of electrons are somehow linked if you could devise some kind of complicated equation... so if the voltage was large enough, then the electron will jump.
2007-03-20 23:31:24
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answer #4
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answered by nassafellow 2
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Above explanations are correct. But now think of it in this way.
The drift velocity of electrons in a wire is not very high and its mass is too less. Hence it has a very less momentum. The rest of the wire (without the electron) has a net positive charge which attracts the electron and arrests its motion.
Simple, isn't it?
2007-03-20 22:56:20
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answer #5
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answered by Ankit 2
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Ah ah but they do jump! Do you know what arcing is? When you open a circuit a voltaic arc is open too for a while. Its strenght depends on the current intensity that is previosly flowing .
2007-03-21 01:35:53
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answer #6
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answered by M.M.D.C. 7
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