why is 321 equivalent to 123 mod 6?

Answer 1

the mode steps are
if a=b(modm)
(note that here = should be considered as mod sign)
then m divides a-b
as m/a-b
here 321=123mod6
then 6 divides 321-123
6/321-123= 6/198
and also 6/198 =36
also 6/321 and 6/123
if 6/321 then 6 cant divide 321 and 6 cant divide 123
thts why the reason for this problem in the previouse asnwer is not correct so for more satisfactio you should apply to
www.mathforum.org and join the section "ask doctor math "
follow the steps and post your dilemma

Answer 2

Because they both have the same remainder 3 when divided by 6.