4y - 3 [x - 2 ( 3 - 2x) - 4y]
2007-03-20 18:53:30 · 4 answers · asked by tico 1 in Education & Reference ➔ Homework Help
just remember to use BEDMAS
Brackets
Exponents
Division
Multiplication
Addition
Subtraction
4y - 3 [ x - 2 ( 3 - 2x ) - 4y ]
4y - 3 [ x - 6 + 4x - 4y ]
4y - 3 [ 5x - 6 - 4y ]
4y - 15x + 18 + 12y
16y - 15x + 18
2007-03-20 18:58:21 · answer #1 · answered by Moo 4 · 0⤊ 0⤋
Ok, what you do is start by distributing the -2 into the (3-2x) part and get the problem
4y-3[x-6+4x-4y]
Then distribute the -3 into the brackets and get
4y-3x+18-12x+12y
Then combine like terms and simplify further:
-15x+16y+18
2007-03-21 02:03:33 · answer #2 · answered by grl4nascar82000 1 · 0⤊ 0⤋
4y-3(x-6+4x-4y)
4y-3(5x-4y-6)
4y-15x+12y+18
16y-15x+18
2007-03-21 01:59:42 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Do ANY of you do your own work? Damn! Cheating it rampant!
2007-03-21 02:12:59 · answer #4 · answered by MissWong 7 · 0⤊ 0⤋