In a senior high practical, i poured 100 mL H2O into an insulated flask with 53g of stainless steel and using a tain probe measured the change in temp over time. Assuming the probe and flask's impact is negligible, how do I calculate C stainless steel. What numkbers do I put where, and how does this related to Qlost = Q gained?? THANKS!
2007-03-20 15:34:43 · 2 answers · asked by markonici 2 in Science & Mathematics ➔ Other - Science
You need the temperature of both the water and the stainless steel at two different times, and they have to be at different temperatures to start with. Then you calculate the specific heat of the stainless by assuming that whatever heat is gained by the water is lost by the stainless or vice versa: ΔQ(stainless) = -ΔQ(water), where ΔQ(water) = ΔT(water)·c(water)·m(water). Then you calculate c(stainless) as the change in heat divided by the mass times temperature change of the stainless. This is assuming that heat transfer to the walls of the flask is negligible.
2007-03-20 16:31:44 · answer #1 · answered by injanier 7 · 0⤊ 0⤋
Q = mC(t final - t initial)
C = Q/(m(T final - T initial)
where C = specific heat capacity
m = mass of steel
and T = temperature
2007-03-20 23:06:29 · answer #2 · answered by mrsbrainiac314 3 · 1⤊ 0⤋