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A transformer with 2600 turns on the primary and 330 turns on the secondary is used in an electric slot car racing set to reduce the input voltage amplitude of 170 V from the wall output. The current in the secondary coil is of amplitude 1.6 A. What is the voltage amplitude across the secondary coil and the current amplitude in the primary coil?

Please help me with this... physics has been beating me the whole semester

2007-03-20 14:37:50 · 2 answers · asked by Sir Guitarist 2 in Science & Mathematics Physics

2 answers

Since the coil ratio is 2600/330 = 7.787, the voltage on the secondary will be 170/7.787 = 21.8V
By the same reasoning, the primary current is 1.6/7.787 = .2 A.

Rule 1: Ip*Np = Is*Ns
Rule 2: Vp/Np = Vs/Ns

2007-03-20 14:52:37 · answer #1 · answered by Steve 7 · 1 0

it truly works out to be the correlation of two motions. One is horizontal action, defined by means of x=vt, the different is vertical action, defined by means of y=(gt^2)/2, the place g = 9.8 m/s^2. you're utilising the valuables that t is equivalent in the two equations. Use t = x/v, plug into the equation for y, use x = 13.5 m and y = a million.40 m, then clean up for v, which may be the speed which you're fixing for.

2016-12-19 10:13:19 · answer #2 · answered by ? 4 · 0 0

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