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I've spent a total of 3 hours trying to get through 3 problems... I need help with this and my online tutor setup is no longer used in my school so I'm totally lost.

Here is my problem:

A solenoid of length 2.8cm and diameter 0.75cm is wound with 160 turns per cm. If the current in the solenoid is decreasing at a rate of 35.0 A/s, what is the induced emf in one of the windings? in the entire solenoid.

I have no idea how to set up this problem and how to do it!! My professor doesn't show us how to solve these kinds of equations... the textbook doesn't help either... I'm not a physics major... I'm a med student who has to pass this class to move on down the college road...

2007-03-20 14:29:26 · 2 answers · asked by Sir Guitarist 2 in Education & Reference Homework Help

2 answers

that is so weird, i have a college physics exam on that too! here's the formula to solve it:
induced emf is equal to the negative inductance times the current rate.
so inductance is equal to the (mu knot (4 pi times 10^ -7) times 16000 squared times the area of the solenoid) divided by the length of the solenoid.
plug that number in to the induced emf formula so it should be -L *the rate (make sure the rate is negative since it's decreasing!)

2007-03-20 14:34:29 · answer #1 · answered by stitchfan85 6 · 1 0

So you must follow a steady drive of 4x the burden of the item to transport it at five g's: F = m*a m*g + implemented = m*five*g What approximately a double wheel? A massive wheel with a small wheel in its middle. You follow a mass to an arm at the better wheel. This creates a torque of the mass occasions the radius of the better wheel. You wrap a rope across the smaller hooked up wheel. The radius of the smaller wheel is a smaller second arm, that means it's going to broaden a larger drive at the rope to stability the massive torque. Since its your homework, I will can help you determine the entire main points just like the wheel radii you desire to make use of, and so forth.

2016-09-05 09:58:41 · answer #2 · answered by kuo 4 · 0 0

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