how many btu are required to heat 1000 lbs of magnesium metal from 60 to 160 degrees fahrenheit?

Answer 1

The basic equation is

q = m Cp delta T

A BTU is the heat to raise 1 lb. of water 1 defree F.

You may not find the Cp of Mg. in BTU's, but you should be able to easily find it in calories or joules. If in calories, then it will be the same value in BTU's. If in joules, divide by 4.184.

You have the mass of 1000 lbs. and the delta T of 100 oF. All you need is the Cp and you are done.

Answer 2

I'll have to work in Metric first.

1,000lbs = 2.2kg
Specific heat of Mg = 1.02kJ/kg/K (In this case K & C give the same difference)

ΔT = 100°F = 37.8°C

2.2 x 1.02 x 37.8 = 84.823kJ

1 Btu = 1055J

84823 ÷ 1055 = 80.4 Btu of heat required.

(I'm pretty sure that's OK)