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sufficient water to prepare 2.75 L of solution?

2007-03-20 13:28:20 · 2 answers · asked by Bri 3 in Science & Mathematics Chemistry

2 answers

145g NaCl (1mol/58.44g NaCl) = 2.48 mol NaCl

molarity = mol/L = 2.48mol/2.75L = 0.902 M

2007-03-20 13:34:22 · answer #1 · answered by hannah_kf 3 · 0 0

NO this is not "C" ITS "D" MOLARITY IS form of MOLES IN ALITER OF a answer SO DIVIDE the load OF SODIUM CHLORIDE WITH ITS MOLECULAR WEIGHT AND DIVIDE the effect WITH THE form of LITERS

2016-11-27 01:46:11 · answer #2 · answered by lunger 4 · 0 0

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