the forklift raised the 180 kg pallet a distance of 1.7 meters. how much work was done? if it raised the pallet in 7 seconds, what was the average power consumption?
2007-03-20 13:26:33 · 2 answers · asked by mandy 1 in Science & Mathematics ➔ Physics
In this case, the forklift is doing work against gravity.
W = F * d * cos θ
W = work done
F = force (in this case, gravity, so F = mg)
d = distance the force was applied
θ = the angle between the distance and the force
Since the force is straight up, and the displacement of the box is straight up, θ = 0º.
W = F * d * cos θ
W = (mg) d cos θ
W = (180 * 9.8) (1.7) cos 0º
W = 2998.8 J
So about 3000 J of work.
Power is work / time
P = W / t
P = 3000 / 7
P = 430 W
The unit for work is Joules. The unit for power is Watts.
2007-03-20 13:39:26 · answer #1 · answered by Boozer 4 · 0⤊ 0⤋
Check out the formulas in your textbook. What a boring question.
some hints:
pe = mgh
power = work/time
I will not let you cheat on your homework. You have to learn this stuff on your own.
2007-03-20 20:31:35 · answer #2 · answered by Anonymous · 0⤊ 1⤋