An electric car is designed ro run on a bank of batteries w/ a total potential difference of 18 V and a total energy storage of 1.3 x 10^7 J. if the electric motor draws 9.6 kW , what is the current delivered to the motor?
Also if the car moves at a steady pace speed of 30.0 m/s hor far will the car travel before it is out of juice.(assume is draws 9.6 kW)
Problem: i know i need (current I) but i have too many variables to use
i used P= V x I to get 722222.2 but it seems wrong
can you help me out?
2007-03-20 11:43:33 · 2 answers · asked by TheThing 2 in Science & Mathematics ➔ Physics
Chris J is right, it is 533.33 amps. The speed and distance the vehicle will travel are "trash" information. That is only given to confuse you. The amps drawn are all that matters, and Power/Volts is the right formula. To find how long the batteries will last, divide the total stored energy by your 9600 watts. That should give you the time the energy will last.
2007-03-20 17:17:43 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Current = power / voltage. Which should come out to 533.33 Amps. That still seems high, but that's the right equation.
2007-03-20 11:50:10 · answer #2 · answered by Chris J 6 · 1⤊ 0⤋