I don't need help solving for x and y. Just setting up the equations.
A freight train and an express train leave towns 390 km apart, traveling toward one another. The freight tarin travels 30 km per hr slower than the express train. They pass one another 3 hr later. What are their speeds?
I know one equation I get from this word problem is E = f - 30, i think. But I can't figure out how to set up the second equation.
2007-03-20 10:02:03 · 4 answers · asked by World Expert 1 in Education & Reference ➔ Homework Help
oops, F=3-30..i knew that..lol
2007-03-20 10:19:10 · update #1
I mean f=e-30...lol.
2007-03-20 10:19:56 · update #2
390 = 3(2x-30)
solve for x ; x being E in your original equation
your equation is flawed. it should be f=e-30
2007-03-20 10:07:57 · answer #1 · answered by Anonymous · 0⤊ 0⤋
It looks to me the equation would be....
390 = 3(E) + 3(E-30)
2007-03-20 10:14:06 · answer #2 · answered by Travis L 1 · 0⤊ 0⤋
F is the cost of the freight prepare 3F is the area of the freight prepare E is the cost of the explicit prepare 3E is the area of the explicit prepare T = 3 D= 390 E = F + 30 3E + 3F = 390 (at the same time they hide the finished distance) divide by utilising 3 E + F = one hundred thirty Sub F+30 +F = one hundred thirty 2F = one hundred F = 50 E = 50 + 30 E= 80 The freight prepare is vacationing at 50 kmh and the explicit prepare is vacationing at 80 km h
2016-10-02 11:25:18 · answer #3 · answered by gregersen 4 · 0⤊ 0⤋
you use the d=rt (distance=rate x time)
so 390=d
390=30d x t
390=d x 3t
im pretty sure. hope that helps iknow 4 sure thats the formula you use.
2007-03-20 10:14:13 · answer #4 · answered by Anonymous · 0⤊ 0⤋