the second of 3 numbers is 1 less than the first. the 3rd number is 5 less than the second. if the first number is twice as large as the 3rd, find the 3 numbers.
2007-03-20 08:04:46 · 3 answers · asked by aviator 5 in Education & Reference ➔ Homework Help
how do u set up the equation...i can solve...
2007-03-20 08:10:11 · update #1
Let x, y, and z be the three numbers.
x = 2z
y = x-1
z = y-5
Substitute the new values for the numbers.
x=2z
x=2(y-5)
x=2y-10
x=2(x-1) -10
x=2x-2-10
x=2x-12
x+12=2x-12+12
x-x+12=2x-x
12=x
So, if x = 12, then y =11, and z = 6 (which is half of x, so that is a good check for that criteria)
2007-03-20 08:17:35 · answer #1 · answered by Lillian L 5 · 1⤊ 0⤋
12,11 and 6
2007-03-20 15:28:34 · answer #2 · answered by Anonymous · 0⤊ 0⤋
12,11,6
2007-03-20 15:12:05 · answer #3 · answered by Anonymous · 0⤊ 0⤋