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triangle ABC. In this case, P and Q coincide, and you must show that PA is parallel to XZ.

Theorem 3.1 : Choose a point P on the circumcircle of triangle ABC and let Q be the other point where the perpendicular to BC through P meets the circumcircle. Let X be the point where this perpendicular meets line BC and let Z be the point where the perpendicular to AB through P meets AB. If Q is different from A, then Z lies on the line parallel to QA through X.

2007-03-20 03:37:03 · 1 answers · asked by MatheMathe 2 in Science & Mathematics Mathematics

1 answers

I don't see how the perpendicular to BC can be tangent to the circumcircle.

2007-03-22 16:28:31 · answer #1 · answered by nor^ron 3 · 0 0

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