2007-03-20 02:52:43 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Zoology
In the average adult human with 206 bones the skeleton comprises approximately 20% of the total body weight.
Equation: 20% x tbw = sw
example-- 20% x 200lbs tbw (total body weight)= 40lbs sw (skeletal weight)
2007-03-20 05:01:06 · answer #1 · answered by Country Hick 5 · 0⤊ 0⤋
Wrong. The average human body contains slightly less than enough bones to form a human skeleton. There are far more amputees in the world than people with 'too many' bones.
2016-03-16 23:25:45 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Between 10-15 percent of body weight in a healthy human being. So, for a 180-pound man, between 18-27 pounds.
2007-03-20 03:26:24 · answer #3 · answered by Brian L 7 · 0⤊ 0⤋
This actually will depend on when you weigh it. Fresh bone weighs a lot more than dry bone, due to the marrow, grease, and moisture still contained within it. Dry bone will weigh less, and weathered, dry bone will weigh even less (due to leaching of minerals out of the bones, and, to a lesser extent, loss of bone flakes).
2007-03-21 12:54:01 · answer #4 · answered by Anonymous · 1⤊ 0⤋