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answers will be given next week

2007-03-20 02:10:59 · 9 answers · asked by Anonymous in Science & Mathematics Mathematics

9 answers

Notice that 0+100=100, 1+99=100, 2+98=100, ...
And you have 50 lots of them (0 up to 49 paired); so 50*100=5000. Then you add the middle 50 to it:

5050


Extra info:
---------------
Gauss was asked this question by his teacher when in primary school (the teacher wanting to keep him occupied for a while); Gauss gave the answer almost immediately -- and it is believed that he used this very method to do it.

But as has been mentioned below -- there are general equations to find the sum of series up to the nth term:

S = n(a+l)/2
S = n(2a+(n-1)d)/2

2007-03-20 02:15:04 · answer #1 · answered by Anonymous · 2 0

Member since: March 18, 2007
Total points: 257 (Level 2)
Points earned this week:
--%Best answer

ozo
0



Notice that 0+100=100, 1+99=100, 2+98=100, ...
And you have 50 lots of them (0 up to 49 paired); so 50*100=5000. Then you add the middle 50 to it:

5050

2007-03-20 10:38:48 · answer #2 · answered by Oyindamola I 2 · 0 0

This the sum of the first 100 terms of the arithmetic progression that starts at 1 and has constant r =1. We know that the sum of the first n terms of an arithmetic progression that starts at a_1 and has constant r is given by S(n) = ((a_1 + a_n)n) /2.

In our case , it's kinda simple, we have a_1 =1 , n =100, a_n =100 and r =1. Therefore, our sum is S(n) = ((n+1)n)/2. Letting n =100, we get S(100) = (101 . 100)/2 = 5050

2007-03-20 09:43:01 · answer #3 · answered by Steiner 7 · 0 0

There is a formula to calculate questions like this, which is:
Number of terms(1st term + last term)/ 2.

So the answer to this question is:

101(1+100)/2= 5050

2007-03-20 09:17:41 · answer #4 · answered by mcfever 2 · 0 0

to add any numbers [n(n+1)]/2 is used where n is the last digit till u want the sum.
Here, n=100 so by substituting in above formula,
we get-----=[100*(100+1)]/2
=5050
u can check it!!

2007-03-20 09:21:38 · answer #5 · answered by shrikant v 2 · 0 0

Sum = (100/2)[1+100) = 5050

Formula used is
Sn = (n/2)(a+l)

2007-03-20 09:59:38 · answer #6 · answered by Adrianne G. 2 · 0 0

it is a serie form of

n(n+1)/2 = 100(100+1)/2 = 5050

2007-03-20 09:20:04 · answer #7 · answered by tuoidabuon 2 · 1 0

i agree with ozo and that is the answer i would have given to you myself pick one from each side they will give you hundred
then multiply by 50
100 * 50 =5000 +50 = 5050

2007-03-20 09:19:18 · answer #8 · answered by emy 3 · 0 0

(100+1) + (99+2) +....(51+50)
(101) + (101) + ... (101)
101 X 50
= 5050

2007-03-20 09:18:43 · answer #9 · answered by DJ 3 · 0 0

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