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The box needs to measure 10cm by 5cm by 5cm; 10% will be wasted in the cutting process. How much cardboard do you need??

2007-03-19 22:05:36 · 3 answers · asked by the CHEVY man 1 in Science & Mathematics Mathematics

3 answers

total surface area of the box
= 2(10*5) + 2(10*5) + 2(5*5)
= 100 + 100 + 50
= 250 cm²

since 10% will be wasted, this is the amount of cardboard you'll need:

250*(110%)
= 250*1.1
= 275 cm²

2007-03-19 22:11:28 · answer #1 · answered by zzzonked 2 · 2 0

Surface area = 2(10 x 5) + 2(5 x 5) + 2(10 x 5)
= 250 cm²
Start with Y cm²
10% is wasted so finish with 90% Y = 0.9Y
Thus 0.9Y = 250
Y = 250 / 0.9 = 278
You need 278 cm² to nearest cm²

2007-03-20 00:18:06 · answer #2 · answered by Como 7 · 0 0

First answer is pretty close, but I expect the wastage is 10% of what you start with, not of what you end with.

So 90% of amount needed = 250
Divide by 0.9:
100% of amount needed = 277.777....

To check this, start with this amount and subtract 10% of it, you get 250.

Start with 275 and subtract 10%, you get 247.5

2007-03-19 22:40:48 · answer #3 · answered by Hy 7 · 0 0

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