in triangle ABC,AB=6cm, AC=8cm and BC=12cm. Angle ABC=26.4 degree. Calculate the area of the triangle ABC?

Answer 1

You can calculate a area of any ABC triangle when you know the length of AB,BC and AC. We call it Herong.

Use this:

S= square root [p x (p-AB) x (p-BC)x (p-AC) ]
with p = (AB + BC + AC)/2

Answer this problem:
p= (6 +8 +12) /2 = 13
=> S=square root(455)= 21.330729007701542

Answer 2

A triangle won't be able to have 3 ninety degree angles; it doesn't be a triangle yet somewhat a rectangle. Why? All 3 angles of a triangle upload as a lot as one hundred eighty tiers, and ninety * 3 = 270 it extremely is larger than one hundred eighty. i love dr bob's answer; even if in case you draw a triangle on a sphere it is going to now no longer be called a triangle; a triangle is a 2-d merchandise, and that can make it three-D.

Answer 3

s = (6 + 8 + 12)/2 = 13
A = √13(7)(5)(1)
A = √455
A = 21.330729007701541750886391521344

A = (1/2)(12)(8)sin(26.4)
A = 21.34248860087651923091231429258

The two are equal if rounded to 3 significant digits. The area by Heron's formula is the more exact.