let f(x)=x^5+2x^3-2
use the newtons method to approximate the zero to 5 decimal place accuracy
can u please show me step by step because i just cant seem to get it right and i want ot know what im doing wrong. thank you!!
2007-03-19 17:29:37 · 2 answers · asked by Fahion_Gal 1 in Science & Mathematics ➔ Mathematics
Newton's method : x_n+1 = x_n + f(x_n)/f'(x_n)
f '(x) = 5x^4 + 6x^2
So you pick any number close to the true zero, which using the sign test is at least between -1 and 1, and plug it into Newton's.
x + (x^5 +2x^3 - 2) / (5x^4 +6x^2)
This will get you a new number which you just plug back in again, and keep doing it until you get the desired accuracy.
2007-03-19 17:40:45 · answer #1 · answered by tryzub91 3 · 0⤊ 0⤋
These links will show you a lot easier than trying to write it out here. Check them out...
http://www.ugrad.math.ubc.ca/coursedoc/math100/notes/approx/newton.html
http://www.cs.utah.edu/~zachary/isp/applets/Root/Newton.html
http://en.wikipedia.org/wiki/Newton's_method
2007-03-19 17:39:27 · answer #2 · answered by Joni DaNerd 6 · 0⤊ 0⤋