2007-03-19 16:55:13 · 7 answers · asked by Tarded H 1 in Science & Mathematics ➔ Chemistry
NO2 reduced to NO (loss of oxygen) and SO2 oxidized to SO3 (gain of oxygen).
2007-03-19 17:01:50 · answer #1 · answered by Brewmaster 4 · 0⤊ 0⤋
NO + SO3 oxidized NO2 + SO2 reduced
2007-03-19 16:58:08 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Nitrogen is reduced from +4 to +2 ,so NO is reduced(oxidizing agent)
sulphur is oxidized from +4 to +6 ,so SO3 is the reducing agent
2007-03-19 17:49:26 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Nitrogen is reduced from +4 to +2, sulfur is oxidized from +4 to +6.
2007-03-19 17:02:49 · answer #4 · answered by TheOnlyBeldin 7 · 0⤊ 0⤋
NO is reduced, SO3 is oxidized...which means that the NO is the oxidizing agent and SO3 is the reducing agent
2007-03-19 17:13:57 · answer #5 · answered by Edward T 1 · 0⤊ 0⤋
Check the oxidation states of all atoms
N(4+) O2 + S(4+) O2 ---> N(2+) O + S(6+) O3
N is from 4+ --> 2+
=>gained electrons/ reduced
S is from 4+ --> 6+
=>lost electrons => oxidized
oxidation is losing electrons, reduction is gaining electrons, (OILRIG)
=> S
2007-03-19 17:02:34 · answer #6 · answered by Alan V 3 · 0⤊ 0⤋
Your equation isn't balanced. it is going to be: 2SO2 + O2 --> 2SO3 The style of moles of SO2 used = 128.12/ sixty 4 = 2 mol From the equation, 2 mol of SO2 want one million mol of O2 So, the style of moles of O2 needed is one million mol of O2 or 32g
2016-12-18 18:26:31 · answer #7 · answered by ? 4 · 0⤊ 0⤋