Math help please.?

Question

How do you rewrite 4/3x^1.2 so that it will look like y=ax^n?

r(x)= 4/3x^1.2 Rewrite it to get the derivative of the function. for example 1/x^2 would be x^-2. So then i can use the equation y=ax^n to get the derivative.

Answer 1

Ah. That's better.
Since r(x) is another way of writing y, y=4/3x^1.2
I will assume the 4 is in the numerator and the rest is in the denominator (since otherwise you would already have it in the correct form).
So...
y= 4/3(x^1.2) = 4/3 [times] 1/(x^1.2) =

4/3 [times] x^-1.2
This is now in the form you asked for where a=4/3 and n=-1.2
and of course y= r(x)

I hope that helps.