Mols/percent yeild?

Question

A solution containing .10 mols of BaCl2 is mixed with a solution containing .20 mols of Na2SO4 to give a precipitate of BaSO4. What is the maximum percent yeild in moles of BaSO4? in grams?

Answer 1

The reaction is BaCl2 + Na2SO4 --> BaSO4 + 2NaCl
mole mole mole 2 moles

Moles of BaCl2 = 0.1 (in 1 L) Moles of Na2SO4 = 0.2 (in 1 L)

moles of BaSO4 = 0.1 (using up all the BaCl2) Look up the molecular mass of BaSO4 to get grams.