A 0.145 kg baseball pitched at 37.0 m/s is hit on a horizontal line drive straight back toward the pitcher at 52.0 m/s. If the contact time between bat and ball is 1.00 10-3 s, calculate the average force between the ball and bat during contact.
N
I don't know what to do with the two speeds.
2007-03-19 12:44:53 · 2 answers · asked by beast 1 in Science & Mathematics ➔ Physics
Let's say the ball was first going in the +X diection away from the pitcher at 37m/s. After it was struck by the bat, it travels in the -X direction at 52m/s towards the pitcher.
Accleration is the CHANGE in velocity divided by time:
a=(v1-v2)/t = [+37 - (-52)]/0.001 = 89,000 m/s^2
The average force during contact is then just mass times acceleration F=m*a:
F=0.145kg * 89000 m/s^2 = 12,905 N
2007-03-19 13:02:47 · answer #1 · answered by Elisa 4 · 0⤊ 0⤋
Well, you would need the two speeds for the impulse.
F=m(v-u)/t
=0.145 kg(52-37)/1.00X10-3
=2175N
I hope this helps. :)
2007-03-19 19:57:32 · answer #2 · answered by Juni Mccoy 3 · 0⤊ 0⤋