this said write an equation for line described using mx+b slope2, (-3,-1)?

Answer 1

y-y1=m(x-x1) m=slope and then put in your co-ordinates
y-(-1)=2(x-(-3))
y+1=2(x+3)
y+1=2x+6
y=2x+5

Answer 2

Linear lines are written in the form y=mx+b, where m is the slope and b is the y-intercept

In this case since slope is give then m = 2.

Then the equation is

y = 2x + b

To find the y-intercept, just sub in the point (x,y) for the x and y in the equation.

-1 = 2(-3) + b
b = -1 + 6 = 5

Therefore the Equation is y = 2x +5

Check to see if the answer is correct, sub the point back into our finished equation.

-1 = 2(-3) + 5
-1 = -1

Therefore left side = right side and we have the correct answer.

Answer 3

y = mx + b, where m is slope and b is y -intercept. Plug in what you know, and solve for what you don't.

-1 = (2)(-3) + b
-1 = -6 + b
5 = b

y = 2x + 5

Answer 4

y=mx+b
y=2x+b
-1=2(-3)+b
5=b
therefore the formula is y=2x+5

Answer 5

use point slope form

y+1=2(x+3)

do the math from there

Answer 6

well i hate doing this stuff but just plug the stuff in 2(-3)+(-1) chyeaaa

Answer 7

well the epuation would be 2x +5.

Answer 8

for y=mx+b

m=slope
b=y intercept

x and y are just coordinates.