Suppose 25.65mL of 0.106M NaOH solution is required to completely react 10.00mL of HCl
2007-03-19 12:30:48 · 4 answers · asked by bigtex24769 1 in Science & Mathematics ➔ Chemistry
NaOH + HCl -> NaCl +H20
Relevant mole ratio:
1 mole + 1 mole
No of moles of NaOH = Concentraion x volume (litres)
= 0.106 x 0.02526 = 0.0027 moles
0.027 moles NaOH would react with 0.027 moles HCl
Conc. of HCl = No of moles / Volume (litres)
= 0.027 / 0.010 = 0.27 Moles per litre
2007-03-19 12:38:53 · answer #1 · answered by Maureen 3 · 0⤊ 0⤋
SInce OH- and H+ react 1:1,
0.106 (mole/L) * (25.65 mL/10.00mL) = 0.272 mole/L
Done.
2007-03-19 19:37:45 · answer #2 · answered by Jerry P 6 · 0⤊ 0⤋
m1v1=m2v2
(.106M)(25.65 mL)= (x M)(10 mL)
the molarity of HCl is therefore .27189 M :)
2007-03-19 19:35:51 · answer #3 · answered by eureka4sureka 1 · 0⤊ 0⤋
God, i hate chemistry!
i really need a tutor
[sorry i cant help, i just wanted to comment =)]
2007-03-19 19:33:37 · answer #4 · answered by Anonymous · 0⤊ 0⤋