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2,3 dimethylheptane
2,4 diethyl - 1 pentene
4 bromo, 2 methyl, 1 heptyne
2 methyl- cyclohexanol

2007-03-19 11:33:33 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

4 answers

Without limited graphics, this is not easy!!!

To use the first, 2,3 dimethyl heptane as an example:
Draw out your 7 carbon spine first then add methyl groups at the second & third carbons
The pentene needs the double bond between the first & second Cs, as well as ethyl (2C) side chains at the 2 & 4 Cs
The heptyne is nasty & I think a trick question as the 2C would have to have 5 bonds
Cyclohexanol is a six C ring molecule with an OH at the top (the 1C) & the methyl at the next C clockwise

2007-03-19 12:00:30 · answer #1 · answered by Spike J 3 · 1 0

1). CH3-CH(CH3)-CH(CH3)-CH2-CH2-CH2-CH3
(For some reason, the last CH3 isn't showing up !)

The two Methyl groups are branches off the 2nd and 3rd Carbons in the Heptane chain.
= 2,3, dimethyl heptane.

2). CH2=C(C2H5)-CH2-CH(C2H5)-CH3

The two Ethyl groups are branches off the 2nd, and 4th Carbons in the Pentene chain with the double bond between Carbons 1 and 2.
2,4, diethyl-1-pentene.

3). CH≡C-CH2-CHBr-CH2-CH(CH3)-CH3.

In the Heptyne chain, Bromine attached to the 4th Carbon, Methyl group branches off the 2nd Carbon from the right, and the triple bond between Carbons 1 and 2.
4, bromo, 2-methyl-1-Heptyne.

4... CH2-CH(CH3)-CH(OH)-CH2-CH2-CH2

Ring structure, the Methyl group branches off the 2nd Carbon, the OH group branches off the 3rd Carbon.
2, methyl-cyclohexanol

2007-03-19 22:12:35 · answer #2 · answered by Norrie 7 · 0 0

start by writing out the biggest chain (e.g., if it's a pentane, go ahead and write 5 C's). Then number them. Then go down the numbers and add whatever needs to be added on them, either additional elements or bonds.

2007-03-19 18:54:10 · answer #3 · answered by Strix 5 · 0 0

Write out the last "base" molecule first. Number everything starting at one end and put all the groups based on the number listed.

2007-03-19 18:49:46 · answer #4 · answered by bourgoise_10o 5 · 0 0

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