algebra homework?

Question

Solve: m² + 3m + 2 = 0

Simplify: 9a + 7 - 2a + b

Answer 1

mk well for the first one you need to simplify it by turning into two binomials that when multiplyed together will give you the original equation. you need to think of two numbers that when multiplied together give you the third monomial in the equation, but when added together give you the second monomial in the equation. so you need to think of two numbers that when multiplied together equal 2, but when added together equal 3. the answers are 1 and 2. now that you have these answers you can divide the trinomial into two binomials:

(m+2)(m+1)

when you multiply this out you get your original equation. now set both of these binomials to zero.

m+2=0 and m+1=0. now solve.

m=-2 and m=-1
those are your answers

for the second equation:

9a+7-2a+b

group like terms so your equation looks like this:

9a-2a+7+b

so now since 9a and 2a are like terms, you can add and subtract them like regular numbers. so you get 7a. this all that you can do to this equation so your final answer is

7a+b+7

Answer 2

Try a little breakdown:
m² + 3m + 2 = 0
--> m² + m + 2m + 2 = 0

Try this kind of factoring (if you're not sure how to just jump straight to the answer):
m(m+1) + 2(m+1) = 0

Factor out that m+1 and we'll get: (m+1)(m+2)=0

Find the values of m that'll make the whole thing 0. So here we can break them down to:
m+1=0, m+2=0
--> m = -1, -2


9a + 7 - 2a + b
Rearrange this around and compute:
9a - 2a + 7 + b = 7a + 7 + b

From there, you could group up something like this:
(7a+7) + b

In that paranthesis, you could see that a common number and/or variable you can factor out is 7:
7(a+1) + b

Answer 3

m = -2

7(a+1) + b

Answer 4

m=-2

14+(a+1)+b