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54.53%carbon, 9.15%hydrogen, and 36.32%oxygen; experimental molar mass 88

2007-03-19 09:51:48 · 1 answers · asked by xxlore09xx 1 in Science & Mathematics Chemistry

1 answers

Divide 54.53 by 12, 9.15 by 1 and 36.32 by 16.

Then see how you can scale the numbers to get a whole-number ratio.

Then see how the apparent MW of the result fits into the number 88, and adjust accordingly.

2007-03-20 07:25:44 · answer #1 · answered by Gervald F 7 · 0 0

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