I heard on sports talk radio last week there are over 9 quintillion brackets. I believe that is 9 with 18 zeros after it.
Also, there is a website of a mathematician who provides the same quote on his website.
In response to truthbetold's... it would be 2^64 if you count the play-in game, otherwise it would be 2^63 which is 9.223 quintillion not counting the play-in game.
2007-03-19 09:20:00
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answer #1
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answered by Tuck1019 2
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2015-03-17 14:33:15
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answer #2
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answered by ? 1
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its easy, each game can have 1 of 2 possible outcomes. with 64 games, this gives 2^64 or 18 quintillion possibilities... 18,446,744,073,709,551,616.
This is about 18 million trillions.
good luck filling out all those brackets.
if this doesnt seem to make sense, think of a simpler case, how many combination of flipping two coins? its 2^2 = 4. HH, HT, TH, and TT. or 3 coins is 2^3 = 8. HHH, HHT, HTH, THH, HTT, THT, TTH, TTT. you can see how that can be extrapolated to 64 coins, or 64 games in our case, yea?
2007-03-19 10:03:55
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answer #3
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answered by conventional 4
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Exactly 18,446,744,073,709,551,616
Edit: Just so you guys know, that's not a joke. There are 64 games.. 2 ^ 64 is 18,446,744,073,709,551,616
2007-03-22 08:11:50
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answer #4
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answered by Anonymous
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This poem jogs my memory of the JibJab sketch approximately Walmart (shh -er I propose vast field Mart!) I enjoyed this greater for the subject than for the common. It entertained me. Line 3 "a" new drummer thank you!
2016-12-18 17:56:16
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answer #5
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answered by shery 4
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a quick guesstimate would be somehting like 32! plus 16! plus 8! plus 4! plus 2! plus 1 or something.
2007-03-19 09:17:43
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answer #6
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answered by Kyle M 6
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9 quintillion thats
9000000000000000 i think
2007-03-19 10:07:04
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answer #7
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answered by gofightinirish35 2
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