English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

What is the percentage ionization of the solute in a 0.00348 M solution of acetic acid (Ka= 1.8*10-5), in %? I got 7.48%. Can anyone confirm this?

2007-03-19 08:58:43 · 1 answers · asked by Ryan C 1 in Science & Mathematics Chemistry

1 answers

The fraction of molecules ionised is given by root (Ka/0.00348)

Then multiply by 100 to get the percentage.

2007-03-19 20:41:28 · answer #1 · answered by Gervald F 7 · 0 1

fedest.com, questions and answers