I am currently in College Physics 2 and Lab (PHY 2054) and am having a little trouble with a question on the lab that deals with the oscilloscope. This lab is titled "Introduction to the Oscilliscope." Following you will find the question that i need help on...
How does the number of wave cycles seen on a screen for a fixed input frequency vary with the sweep time/division control setting? Why?
Any help would be greatly appreciated.
2007-03-19 08:20:02 · 5 answers · asked by Logan 4 in Science & Mathematics ➔ Physics
"Make sense?"
Yes it does. If i would have only thought about it a little more i could have figured it out.
Thanks all who have answered.
Only if i could choose all as a best answer!
2007-03-19 08:41:01 · update #1
frequency is a function of time, so the larger the time/division setting the more HZ will be seen. Example: with a 60 hz/sec signal, you will have 60 HZ displayed per div. If you set the time/div setting to 1 second. As you decrease the time you will see the signal spread out.
2007-03-19 08:30:37 · answer #1 · answered by Anonymous · 6⤊ 1⤋
the higher the sweep time per division value, the greater the number of waves shown on the screen. If you set the sweep time per div. to 1micro sec and the wave length is 10 micr sec, you will see one complete cycle on the screen.
2007-03-19 08:37:21 · answer #2 · answered by confused 3 · 0⤊ 1⤋
If you set the time to be long, you'll see more cycles.
Suppose the input is 1khz, ie, the period is 1/ (1khz) = 1 ms
If the sweep time is 1 ms, you'll see one cycle. If the sweep time is 2ms, you'll see two cycles. If the sweep time is 1/2 ms (500 microseconds), you'll see a half cycle.
Make sense?
2007-03-19 08:27:24 · answer #3 · answered by Anonymous · 0⤊ 1⤋
I fairly have viewed gadgets on ebay for as low as US$10. (plus delivery) yet there are various distinctive fashions. you would be able to desire to be certain: bandwidth (10MHz is standard, yet one hundred MHz is so lots greater on hand for RF use) style of channels (2 is standard) storage or not (standard not) sensitivities and brought about sweep to examine reveal screen length notice which you will get hardware and application that makes use of a computer as reveal and computing power and has an analog front end. .
2016-12-19 09:01:43 · answer #4 · answered by ? 3 · 0⤊ 0⤋
The sweep will be in time per division. Obviously as you go to a faster sweep (smaller time per division), you will see fewer cycles of your waveform.
2007-03-19 08:24:02 · answer #5 · answered by Gene 7 · 1⤊ 1⤋