The voltage and the current in the primary coil of a nonideal transformer are 120 volts and 2.0 amperes. The voltage and the current in the secondary coil are 19.4 volts and 11.8 amperes. What is the efficiency of the transformer? The efficiency of a transformer is defined as the ratio of the output power to the input power, expressed as a percentage e=100Pout/Pin
2007-03-19 07:03:16 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
e = Pout/Pin * 100%
= ((Vout*Iout)/(Vin*Iin)) * 100%
= ((19.4*11.8)/(120*2)) * 100%
= 95.38%
2007-03-20 02:33:20 · answer #1 · answered by Lilliana 5 · 3⤊ 0⤋
Efficiency of transformer =output power / input power
=19.4 x 11.8 /120 x 2
=95.38%
2007-03-19 07:12:32 · answer #2 · answered by ukmudgal 6 · 0⤊ 0⤋
Power in, 240 watts. Power out, 228.92 watts. The obvious division gives an efficiency of 95.38%, which would be typical for a transformer of that size.
2007-03-19 07:12:06 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I odn't know about all your amperes and voltages, etc. but I can tell you one thing for sure. Having a robot that doubles as a tractor trailer is EXTREMELY efficient, so yes... Transformers are very efficient. I hope to get one myself soon.
2007-03-19 07:11:32 · answer #4 · answered by Anonymous · 0⤊ 0⤋
95.38%
2007-03-20 08:34:33 · answer #5 · answered by joshnya68 4 · 0⤊ 0⤋