The primary coil contains 200 turns. Find the necessary number of turns N2 in the secondary coil.
2007-03-19 06:36:29 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Ratio of number of turns in secondary to number of turns in primary is equal to ratio of current in primary to current in secondary
number of turns in secondary / 200=500/25 = 20.
number of turns in secondary = 20 x 200 = 4000
2007-03-19 07:06:09 · answer #1 · answered by ukmudgal 6 · 1⤊ 0⤋
The voltage should raise the same ratio as the current decreases., ie, 500/25= 20 times. So the secondary coil should have 20 times the number of turns in the primary coil.
I.e. Ns = 20 Np = 20 x200 = 4000 turns
2007-03-19 13:50:29 · answer #2 · answered by M.M.D.C. 7 · 1⤊ 0⤋
Sorry woops
Ip x Np = Is x Ns ==> Ns = 200x500/25 = 4 000
2007-03-19 13:46:50 · answer #3 · answered by physicist 4 · 1⤊ 0⤋
answer is 4000 turns as:
number of turns in 1 x current = number of turns in other x current
2007-03-19 13:48:20 · answer #4 · answered by chrissie 4 · 1⤊ 0⤋