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11 answers

Get a calander
start countin'

2007-03-19 05:56:15 · answer #1 · answered by Anonymous · 0 0

I advocate a four day work week with at least 15 bank holidays and 6 weeks paid holiday pay a year. With weekends, that would get us down to about 160. Quite fitting with all the other things that working detracts from.

--That Cheeky Lad

2007-03-19 08:35:40 · answer #2 · answered by Charles-CeeJay_UK_ USA/CheekyLad 7 · 0 0

here is the calendar for working days in 2007. Bank Holidays are marked

http://transit.metrokc.gov/tops/van-car/vpa/2007calendar.pdf

2007-03-19 05:57:38 · answer #3 · answered by Georgie 4 · 0 0

Well it really depends what job you have. If you are me, there are actually more than 365 working days this year. Everyday is a struggle when you are being held down by "the man"... but if you are my brother, the year will dish out maybe 5 real work days

2007-03-19 05:57:17 · answer #4 · answered by bobby g 2 · 0 0

primary guy or woman works 5 days each and every week. There are fifty two weeks in keeping with 12 months: fifty two x 5 = 260 week days in keeping with 12 months anticipate 20 days trip journeys in keeping with 12 months + 8 economic business enterprise/Public trip journeys 260 - 28 = 232 days economic business enterprise trip journeys selection finding on 12 months, business enterprise etc, however the first is 8 days in keeping with 12 months: 232 - 8 = 232 days labored in keeping with 12 months.

2016-10-19 02:08:24 · answer #5 · answered by balikos 4 · 0 0

365

2007-03-19 06:03:09 · answer #6 · answered by aryen 3 · 0 0

Just get a calendar sweetie since everyone in the world doesn't work the same days in a week.

2007-03-19 05:56:22 · answer #7 · answered by Sugastack 3 · 0 0

Check out this calendar:

http://transit.metrokc.gov/tops/van-car/vpa/2007calendar.pdf

2007-03-19 05:57:48 · answer #8 · answered by paper_boy21 3 · 0 0

I think 273 if you don't work the weekends.

2007-03-19 05:56:52 · answer #9 · answered by Anonymous · 0 0

Too many!

2007-03-19 06:04:19 · answer #10 · answered by Anonymous · 1 0

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