how can I solve this inequation? sqrt (3x)>-1?

Answer 1

First of all what does sqrt stand for? Ahhhhhhhhh square root!

sqrt (3x) > -1
square both sides
3x > -1^2
3x > 1
divide both sides by 3
x > 1/3

i hope that helps....

Answer 2

The above answers are INCORRECT as the sqrt( f(x) )bigger than a negative number means complex numbers. They answers above are only true of sqrt (3x)>+1

Basically, the square root of any positive number is greater than 0, so greater than -1.

The answers above have incorrectly stated that x>1/3, but make x = 0.001 and see that it still works.

Basically, x>0, and for an x <=0, the answer has a complex root including i, so I would put the answer as x>0.

Answer 3

sqrt(3x) > -1
3x > (-1)^2
3x > 1
x > 1/3

Answer 4

x ≥ 0
The square root of of any (non-negative) number is non-negative, so its always greater than -1 in this case.
x cannot be negative, as the square root would become imaginary.

Markymark: you obviously did not read my answer.
Also, your answer is not quite correct, as 0 is a solution.

Answer 5

x > 1/3

sqrt (3x) > -1
3x > -1^2
3x > 1
x > 1/3