i need help with this statistics problem..?

Question

this is the problem...

>> two standard 6-sided dice are rolled, what is the probability of rolling a value larger than or equal to 7 given that each lands on an even number.

Answer 1

if first die is a

6 - 3/3 chance
4 - 2/3
2 - 1/3

for a total of 6/9 chance. That reduces to 2/3, so 2/3 is your answer. You get points for assigning best answers by the way... be kind and give me "best answer" if I helped you. The person below me is 100% wrong, sorry to say... :/

Answer 2

If each lands on an even number then the answer won't ever be 7.

But think about it

There is a 1/6 chance of rolling any of the 6 numbers

When you have 2 die, there is a 1/12 chance of rolling any of the 12 possible numbers (with the highest being 12 - two 6's)

So you need the total to be equal to 8

so the chances of rolling an 8

could be (2,6) (4,4) (6,2)

chances of rolling a 10

in even numbers is (2,8) (4,6) (8,2) (6,4)

Chances of rolling a 12

in even numbers is (4,8) (6,6) (8,4)

So there are 10 options that will give you the answer you are after


But think about the possible answers you'd get with 2 dice

you could get

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1)(2,2)(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2)(3,3)(3,4),(3,5)(3,6)
(4,1)(4,2)(4,3),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

This is all the options = there are 36 outcomes, and 10 of them are ones you would want

so 10/36

thats it ...

Answer 3

hey the probablity comes out to be 1/6.....as there are 6 outcomes to get a sum of even nums greater than or equal to 7.....n total outcomes are 36.......!!!!!!!!

Answer 4

6,6
6,4
4,6
4,4
6,2
2,6

Probability = 6/36 = 1/6